**Introduction To Calculus And Analysis** – Emetics Stack Exchange is a question and answer site for students of all levels and professionals in related fields. It only takes a minute to sign up.

I believe it is not necessary to read the previous pages and the book first as my problem is manipulation and not concepts.

## Introduction To Calculus And Analysis

I can follow the manipulation, but the confusion is how he came to the conclusion

## Schaum’s Outlines Advanced Calculus Second Edition Softcover Reference Book Textbook Vintage

Judging from the text, you are not expected to come up with this formula for $delta$ at this point, or any other suitable formula. The appearance here is just for show: just to show that there’s a formula to make it work.

. Working with the definition of the $epsilon$-$delta$ boundaries is not a “solve for $delta$” problem. If there is a limit, there is a whole range of values for $delta$ that will suffice, and as long as you find

Note that a more general technique is to require $δ=min(1, bar δ)$ so that one can extract a linear factor $δ$ and bind all $δ$ into the remaining factor $1$, $$ to δ. (2|x_0|+δ)le bar δ(2|x_0|+1). $$ has a limit $ϵ$ if $bar δ=frac$ is chosen. All in all, $$ δ=minleft(1, fracright) $$ is a valid choice.

One may have difficulty determining which of these limits is the smallest (actually “$+$” in terms of the concavity of a square root). However, since neither is zero, the expression “$min$” is sufficient for the proof.

### Fractional Calculus Of Variations In Terms Of A Generalized Fractional Integral With Applications To Physics

As indicated in the comments, to satisfy the going concern assumption, $|f(x)-f(y)|<epsilon$ for which we can put $delta(2|x_0+delta )<epsilon$ which is a quadratic inequality, which gives us the given value of $delta$

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